60=-16x^2+96x

Solution for 60=-16x^2+96x equation:

60=-16x^2+96x

We move all terms to the left:

60-(-16x^2+96x)=0

We get rid of parentheses

16x^2-96x+60=0

a = 16; b = -96; c = +60;
Δ = b2-4ac
Δ = -962-4·16·60
Δ = 5376
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{5376}=\sqrt{256*21}=\sqrt{256}*\sqrt{21}=16\sqrt{21}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-96)-16\sqrt{21}}{2*16}=\frac{96-16\sqrt{21}}{32}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-96)+16\sqrt{21}}{2*16}=\frac{96+16\sqrt{21}}{32}
$